Additional Math – Differentiation – Quotient Rule (Challenging)
Differentiate $latex \displaystyle\ y=\frac{{{{x}^{2}}\sqrt{{x+1}}}}{{x-1}}$ with respect to x. Simplify the Numerator (otherwise you need to use both quotient rule for [...]
Differentiate $latex \displaystyle\ y=\frac{{{{x}^{2}}\sqrt{{x+1}}}}{{x-1}}$ with respect to x. Simplify the Numerator (otherwise you need to use both quotient rule for [...]
Use Quotient Rule $latex \displaystyle \frac{{dy}}{{dx}}=\frac{{v\frac{{du}}{{dx}}-u\frac{{dv}}{{dx}}}}{{{{v}^{2}}}}$ Differentiate the variables separately before inserting into the rule, there is less chance of [...]
$latex \displaystyle y={{\cot }^{2}}x-5+\cos ecx$ It is difficult to differentiate cot x and cosec x directly. You need to change [...]
To find the value of k, you need to first find the gradient of the tangent of the curve. Then [...]
$latex \displaystyle \text{y = ln}\sqrt[3]{{\frac{{3x-1}}{{x+5}}}}$ Before you Differentiate, simplify the expression by changing the cube root to index form followed [...]
$latex \displaystyle y=\ \ln \left( {\frac{{{{e}^{{{{x}^{2}}}}}}}{{\cos (1-x)}}} \right)$ Before you Differentiate, simplify the expression using the Laws of Logarithm $latex [...]
$latex \displaystyle y=\ \text{ln}\left( {\frac{{\sin x-1}}{{3x+2}}} \right)$ Use the Law of Logarithm Rule lg (x/y) = lg x - lg [...]
Sun 12 noon Additional Math Tuition Class at Woodlands- Differentiation of gradient to find the equation of curve. [...]